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本帖最后由 shouce 于 2015-11-26 21:34 編輯 + A0 {$ u: e. f
8 n; j4 c& `; {: ?3 e. Z% examlpe7.m
+ F$ n0 t. f1 ?, ]3 |9 F+ g1 h3 ^% [1 ta=0; b=2;4 T) U! X* u1 h5 Z. G0 T5 j
eps1=1e-12;eps2=1e-12;
1 e. `- x2 _! c9 p( z$ X N=300;
5 {& T+ p1 J8 t8 EA=[-0.104020146 35.0002164 -0.004160847];
3 Y( _: n/ M( H, o) O9 C, `[m,n]=size(A);- h6 Q: j/ ~* ?6 l0 _( v
for i=1:m $ B# E7 @* A4 s* _! L- W4 Z
a1=A(i,1);b1=A(i,2);m1=A(i,3);8 Z; ~8 r8 L6 E9 u) K+ R. A: R% [$ u
end/ h/ e; U* q9 ?$ a b, u
f=@ (x) ((285+60*tan(45*pi/180)-b1*sin(x)-a1*cos(x))*(a1+b1*m1)+(60)^2*x*(sin(x)-m1*cos(x))-60*285*tan(45*pi/180)*(m1*sin(x)+cos(x)));5 y4 Q+ k5 g, E
Hfun=@Bisection;4 ~, H4 F" F! R5 v% r5 D5 B& q& J* `2 Y
[k,x,f_value]= feval(Hfun, f,a,b,eps1,eps2,N);2 M6 T- V" s1 F% Z* {8 G
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% A 為離散點(diǎn)坐標(biāo)及導(dǎo)數(shù) 中心距 285 左旋 螺旋角45度 在二分法中增加一部些程序,方便了很多
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: n; }) s0 D F& u! G; b部分運(yùn)行結(jié)果:
2 o' I7 y, L1 v* s4 `' n 35, 1.303240794, 1.303240794, 1.303240794,0.000000896,
. y& o, L, r3 g2 c# ] 36, 1.303240794, 1.303240794, 1.303240794,0.000000279,
8 p$ a B* }3 _6 [. p. e1 L 37, 1.303240794, 1.303240794, 1.303240794,-0.000000030,
. R+ t/ o/ t/ W0 z' g; }# a 38, 1.303240794, 1.303240794, 1.303240794,0.000000124,. a# i" p$ m C5 v7 p7 H* c# N
39, 1.303240794, 1.303240794, 1.303240794,0.000000047,/ n* a0 c7 g# X r
40, 1.303240794, 1.303240794, 1.303240794,0.000000009,
* E$ x1 h6 \! m9 [9 E$ P/ x. @% w, W 41, 1.303240794, 1.303240794, 1.303240794,-0.000000011,( k7 A7 [) W2 R1 J+ ]
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